My name is Tasha Chapman. I'm a full time artist living in Florida, with a love for the ocean and a fascination with nature. My work draws on the shapes and textures of the natural world, the creatures who inhabit it, and all things aquatic. My focus is on clean flowing lines, soft colors, and that overall feeling of joy we experience when we're outside and fully immersed in the natural world.
I started my career as an artist almost 15 years ago and quickly realized that I do my best when I'm free to do my own thing. I became involved in producing freelance art for t-shirt companies, bands, and other similar clients. My work has been featured in Urban Outfitters, Threadless, shirt.woot, and Free People, to name a few.
When I'm not creating you can usually find me by the sea, surfing, diving or just watching the patterns in the water. The ocean landscape is an endless source of inspiration to me, and aquatic themes run throughout most of my work. In 2012 my love of surfing also inspired me to create Chapman at Sea, a line of utilitarian style surfboard bags and beach bags.
You could say Chapman at Sea is my "day job" now, but I still find time to draw and paint. Most recently I've been producing a line of acrylic paintings, exploring the connection between the ocean and the desert.
You might be wondering why this website is called jewelwing.com when my name is Tasha. Here's the story: A long time ago, back when the internet was just being born (or maybe slightly after that) a little girl's especially tech savvy father asked her if she'd like to have a website of her own to show her artwork. He told her to choose a name for the website and, being a little girl, she thought of butterflies, fairies and pretty things that little girls like. The ebony jewelwing is a type of damselfly and when pinkprincessfairy.com didn't work out, jewelwing.com was born. It's been the home of my online portfolio for so many years, whole life really, that it would feel strange to change it at this point, so jewelwing.com is where my work will always be found.